# Functional Programming: Sort an Array Alphabetically

Tell us what’s happening:
Describe your issue in detail here.

After doing the code, mine seems to work but is different from FCC solution. I am a bit confuse with a > b and -1 : 1 solutions. Can someone explain in great depth about it?

``````  **Your code so far**
``````
``````return arr.sort((a, b) => a === b ? 0 : a > b ? 1 : -1)
// this is what I did to pass

return arr.sort((a, b) => a === b ? 0 : a < b ? -1 : 1)
// this is what I found FCC solution
``````
``````  **Your browser information:**
``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/101.0.4951.67 Safari/537.36`

Challenge: Sort an Array Alphabetically using the sort Method

Do you understand how the ternary operator works?

In terms of if/else statements, yours is this:

``````if (a === b) {
return 0;
} else if (a > b) {
return 1;
} else {
return -1;
}
``````

theirs is this

``````if (a === b) {
return 0;
} else if (a < b) {
return -1;
} else {
return 1;
}
``````

The logic is the same, it’s the order of statements that are flipped around.