help---Return Early Pattern for Functions

JavaScript
1

Hi there, can someone explain to me what I’m missing?

Here’s my code so far for this challenge:


// Setup
function abTest(a, b) {
  // Only change code below this line
  if (a < 0 || b < 0);
  return;
  if (a > 0 && b > 0);
  return (a*b) + a;
  if   (a == b);
  return (a*2*b);

  // Only change code above this line

  return Math.round(Math.pow(Math.sqrt(a) + Math.sqrt(b), 2));
}

// Change values below to test your code
abTest(2,2);

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.110 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/return-early-pattern-for-functions

2

If statements look like this:

if (condition) {
  doSomething();
}

The challenge asks you to return if a or b is less than 0. Otherwise just do the calculation that is already present.The challenge does not ask you to do any of these things, not sure why you added them:

if (a > 0 && b > 0);
return (a*b) + a;
if   (a == b);
return (a*2*b);
3

Yes, thank you for responding and taking a look. Originally, I did have it formatted as the following below:

if (a < 0 || b < 0);
return;

However, I seemed to still be missing something. Am I on the right track? I’m unsure what exactly is the missing piece.

4

ahh nevermind. It looks like where I had the colon after the “if” statement I should have had a pair of curly brackets instead.

5

Hey Guys, i was trying to do this challenge, but i don’t get how they got 8 on abTest(2,2)
Math.pow(Math.sqrt(a) + Math.sqrt(b), 2). according to my knowledge back to C, that expression is equal to squareroot of a+ squareroot of b power 2(didn’t get math sign)
can anyone tell me where am wrong

6

Math.sqrt(2) + Math.sqrt(2)
This is 2 * Math.sqrt(2)

This is now squared, so you get 4 * 2 which is 8

This is because the syntax of Math.pow() is Math.pow(base, exponent)
base ^ exponent

If your look Math.sqrt(a) + Math.sqrt(b) is the first argument of Math.pow()

1 Like
7

Ooh now get it. were trying to eliminate squareroot inside the equation. thanks buddy
what about the return?? still getting some trouble with return 0, return 1 and return only.

8

Do you mean the return on the line of that mathematical expression?
It returns the result of Math.pow rounded to the nearest integer (Math.round is the one that makes the rounding - it is needed because of limitations of doing this operations in binary with a limited number of bits available)

Or where?

9

yep agree, but what if we type return 1 instead of return??
BTW what’s the difference btn these two

10

I don’t understand, do you mean difference between

return; // never write this

And

return 1; // this return 1

?

1 Like
11

Yes, cause i get trouble every time i use “return” stuff

12

Never write just return;, make it always return something

13

for this challenge we did it cause we want it to be undefined. am i right??

14

In that case you need to write return undefined

1 Like
15

thanx buddy for the explaination