If type 0 to 9 then set text and a to z also set text

1

https://jsfiddle.net/2xsnawdk/

 $(".writehere1").on('keydown', function() {
   var key = event.which || event.key;
   if (key < '0' || key > '9') {
     $('#test1').html('detect if write number').fadeIn(500, 'linear');
   }
 });

 $(".writehere2").on('keydown', function() {
   var key = event.which || event.key;
   if (key < 'a' || key > 'z') {
     $('#test2').html('detect if write letter').fadeIn(500, 'linear');
   }
 });

So my problem with if not really understand at all. On first input if write a-z to 0-9 works both why? On second input detect nothing?

So want to detect if write only from letters in other cases show nothing and also with numbers.

Thanks!

3

If you write in first input 0 to 9 then show a text with .html function otherwise show nothing. And same with a to z.

Thanks!

5

So you think because string?

 $(".writehere1").on('keydown', function() {
   var key = event.which || event.key;
   if (key < 0 || key > 9) {
     $('#test1').html('detect if write number key ' +key).fadeIn(500, 'linear');
   }
 });

https://jsfiddle.net/bxw2j01y/

So remove string but still why show message if still write only letters not numbers?

Thanks!

7

I plan to event key:

event.key 0 to event.key 9 not like 48 and 57? So cant use this for that detect purpose? As it use event.which?

48

event.key

0

event.location

0(General keys)

event.which[(deprecated)](https://developer.mozilla.org/en-US/docs/Web/API/KeyboardEvent)

48

event.code

Digit0


57

event.key

9

event.location

0(General keys)

event.which[(deprecated)](https://developer.mozilla.org/en-US/docs/Web/API/KeyboardEvent)

57

event.code

Digit9

Thanks!