Tell us what’s happening:
Describe your issue in detail here.
I wrote a code, that relly work properly б and returns everythingб that it need to returnб but when i run testб everything failing (i tried to delete whitespaces and so onб it just don’t passes the testб but it’s work correct). You can try my code and ensureб that it is correctб but i don’t know how to pass though.
**Your code so far**
let numLastArr = [];
function convertToRoman(num) {
const numbers = {
1 : 'I',
4 : 'IV',
5 : 'V',
9 : 'IX',
10 : 'X',
40 : 'XL',
50 : 'L',
90 : 'XC',
100 : 'C',
400 : 'CD',
500 : 'D',
900 : 'CM',
1000 : 'M'
}
// converting taken number into roman number
function conv (num, num2) {
if (num >= 1 && num <= 3) {
let a = '';
while (num >= 1){
a += numbers[num2];
num--;
}
return a;
} else if (num >= 6 && num <= 8){
let a = '';
let u = num - 5;
while (u >= 1) {
a += numbers[num2];
u--;
}
return numbers[5 * num2] + a;
}
return numbers[num2 * num];
}
const myFunc = numer => Number(numer);
let numArr = Array.from(String(num), myFunc);
//if 4 numbers in number
if (numArr.length == 4) {
let fir = numArr.shift();
if (fir <= 3) {
numLastArr.push(conv (fir, (fir * 1000) /fir));
// call func again
return convertToRoman(numArr.join(''));
}
} else if (numArr.length == 3) {
let fir = numArr.shift();
numLastArr.push(conv (fir, (fir * 100) /fir));
// call func again
return convertToRoman(numArr.join(''))
} else if (numArr.length == 2) {
let fir = numArr.shift();
numLastArr.push(conv (fir, (fir * 10) /fir));
// call func again
return convertToRoman(numArr.join(''))
} else if (numArr.length == 1) {
let fir = numArr.shift();
numLastArr.push(conv (fir, (fir * 1) /fir));
// call func again
return convertToRoman(numArr.join(''))
}
let b = numLastArr.join('').trim('').replace(/\s+/g, '');
return b;
}
console.log(convertToRoman(1004));
**Your browser information:**
opera gx
User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/94.0.4606.81 Safari/537.36 OPR/80.0.4170.91
Challenge: Chunky Monkey
Link to the challenge: