Interm. Algorithm Scripting: Seek and Destroy

JavaScript
1

Tell us what’s happening:
I really don’t see atm why this doesn’t work…obviously I’m doing sth wrong.
I thought about a nested for loop at first but then went this way.
When I console.log(args[i]) in the loop i get the value 2 and 3 but later in the filter it seems 2 is being skipped somehow and its returned as well.
Thanks for any help

Your code so far


function destroyer(arr) {



var args = Array.prototype.slice.call(arguments);//convert to array

console.log(args) //test

for (let i = 1; i < args.length; i++) {
  //console.log(args[])// test inside loop
  arr = args[0].filter(word => word != args[i])
}
//arr = arguments[0].filter(word => word != arguments[1] && word    != arguments[2] && word != arguments[3]);// 3 Arguments Hardcoded

return arr ;
}

console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));//output

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Challenge: Seek and Destroy

Link to the challenge:

2

Consider whether you start loop at the correct index and which array should have filtered contents - args or arr.