Intermediate Algorithm Scripting - Arguments Optional

JavaScript
1

Why is this doesn’t satisfy
addTogether(2)([3]) should return undefined .
it dose return undefined
and it already satisfied all the other conditions

function addTogether() {
if(typeof(arguments[0])=== "number"){
    if(arguments.length !== 2){
        return ((y) => {return arguments[0] + y});
    }
      if(arguments[1] !== undefined && typeof(arguments[1]) === "number"){
    return arguments[0] + arguments[1];
      }
  }   
  return undefined;
}

console.log(addTogether(2,[3]));
console.log(typeof([3]));

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Challenge: Intermediate Algorithm Scripting - Arguments Optional

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2

This function will never return ‘undefined’

3

it already satisfied all the other conditions, including returning undefined

4

Not quite. This function that you are returning won’t return undefined at any point.

5

return ((y) => {return addTogether(arguments[0] , y)});

6

But This function DID return undefined, did you even test it?

7

The outer function did return undefined sometimes, but the function you were returning did not have a way to return undefined!

Your update two posts above fixes that issue.

8

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