Intermediate Algorithm Scripting - Arguments Optional

JavaScript
1

Hello everyone, i need someone to explain to me why in FCC solution they wrote first and _$Second in parentheses?

if (typeof (first) === “number” ) 
If (typeof (_&Second) === “number) return first + _$Second;

I WROTE THE SOLUTION LINK BELOW, AND I WROTE THE FULL CODE

function addTogether() {
const [first, _$Second] = arguments;
if (typeof (first) === “number” ) {
If (typeof (_&Second) === “number) return first + _$Second;
If (arguments.length === 1 ) return (_$Second) => addTogether(first, _$Second);
}}

addTogether(2,3);

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Challenge Information:

Intermediate Algorithm Scripting - Arguments Optional

2
  • are you sure?! cause im not seeing it from their provided three solutions!!
  • also you can name a variable in many ways!! you can look it up about “naming convention” of variables

happy coding :slight_smile:

3

They wrote second, i accidentally wrote it like that, but that’s was not my point.

MY POINT IS.

why did they wrote typeof (first)? Why did they put the variable inside parentheses

4
  • you dont have to!! you can simply just write as such typeof first === 'something'

happy coding :slight_smile:

1 Like
5

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