Intermediate Algorithm Scripting - Drop it

JavaScript
1

Tell us what’s happening:
Describe your issue in detail here.

Your code so far

function dropElements(arr, func) {
  let result=[];
  for(let i=0;i<arr.length;i++){
    if(func(arr[i])){
      result.push(arr[i]);
    }
  }
  console.log(result)
  return result;
}

dropElements([1, 2, 3], function(n) {return n < 3; });

the test result is : // running tests

dropElements([0, 1, 0, 1], function(n) {return n === 1;})

should return

[1, 0, 1]

why not [1,1]???
.

dropElements([1, 2, 3, 9, 2], function(n) {return n > 2;})

should return

[3, 9, 2]

why not [3,9]???

. // tests completed // console output
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Challenge: Intermediate Algorithm Scripting - Drop it

Link to the challenge:

2

The instructions:

Given the array arr, iterate through and remove each element starting from the first element (the 0 index) until the function func returns true when the iterated element is passed through it.

Then return the rest of the array once the condition is satisfied, otherwise, arr should be returned as an empty array.

Note the bolded words: “…until the function func returns true … Then return the rest of the array once the condition is satisfied…”

Part of being a developer is reading things very closely.

3

thank you, i know my problem,i got it wrong.so i change it.now it’s ok!

function dropElements(arr, func) {
  let result=[];
  for(let i=0;i<arr.length;i++){
    if(func(arr[i])){
      result=arr.splice(i);
    }
  }
  return result;
}
4

Cool, good job.

I wrapped your answer in [spoiler][/spoiler] tags since it is a working solution to a curriculum challenge.

1 Like
5

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