# Intermediate Algorithm Scripting - Sum All Odd Fibonacci Numbers

Hello guys!
I am stuck with this challenge, I am a newbie so I made up this and it only pass 5/6 and I don’t really know what to do anymore. Can you please take a look?

``````function sumFibs(num) {
let prev = 1;
let curr = 1;
let next;
var sumofOdds = [];
sumofOdds.push(prev);
sumofOdds.push(curr);
for(let i = 0; i<num; i++) {
next = prev+curr;
prev = curr;
curr = next;
// console.log(next)
sumofOdds.push(next)
// console.log(sumofOdds)
};
var odds = sumofOdds.filter((item) => item % 2 === 1);
// console.log(odds);
var total = 0;
for(let i = 0; i<odds.length - 1;i++) {
while (total < num) {
total +=odds[i];
i++;
};
};
}

console.log(sumFibs(75025));
``````

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Challenge: Intermediate Algorithm Scripting - Sum All Odd Fibonacci Numbers

This isn’t what num is for

Or this.

What do the instructions say num is for?

" Given a positive integer `num` , return the sum of all odd Fibonacci numbers that are less than or equal to `num` ." and : " For example, `sumFibs(10)` should return `10` because all odd Fibonacci numbers less than or equal to `10` are 1, 1, 3, and 5. "

Right. So neither of your usages are consistent with that. You need individual numbers that are less than num

1 Like

thanks. i re-write the last part according to your instructions. thank you very much sir.

var odds = sumofOdds.filter((item) => item % 2 === 1);
var finalodds = odds.filter ((item) => item <= num);
var total = 0;
console.log(finalodds)
for(let i = 0; i<finalodds.length;i++) {
total += finalodds[i];
}