Hint #1 informs you to use a nested loop to search through all the elements of the nested arrays while this completely contradicts the solution. I’ve tried solving this using one but to no avail. Is Hint #1 invalid or is there a possible way to do this with a nested loop?
yes, it’s weird. I’m removing the word “nested” from there, and it will make sense
It’s definitely much easier to do it without nested loops but still it’s possible.
Here’s an example solution using two nested loops. There is probably a better way but that’s what I come up with 
function filteredArray(arr, elem) {
let newArr = [];
for (let i = 0; i < arr.length; i++) {
let nestedArr = arr[i];
let hasElem = false;
for (let j = 0; j < nestedArr.length; j++) {
if (nestedArr[j] === elem) {
hasElem = true;
break;
}
}
if (!hasElem) {
newArr.push(nestedArr);
}
}
return newArr;
}
Here’s my solution that worked without realizing I should try to apply indexOf(). I sat down with my developer of a husband and he made me push through this for 30 minutes using only what I can rack up from my noggin.
function filteredArray(arr, elem) {
let newArr = [];
// Only change code below this line
for (let i=0; i<arr.length; i++) {
let includes = false;
for (let j=0; j<arr[i].length; j++) {
if (arr[i][j] === elem) {
includes = true;
}
}
if (includes === false) {
newArr.push(arr[i]);
}
}
// Only change code above this line
return newArr;
Of course my initial gut was “why can’t I google how to check if an array includes an item?” which was met with a blunt reminder that I’m currently coding for the sake of learning coding.
It is great that you solved the challenge, but instead of posting your full working solution, it is best to stay focused on answering the original poster’s question(s) and help guide them with hints and suggestions to solve their own issues with the challenge.
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