Js drop it challenge

JavaScript
1

Tell us what’s happening:
My code works very well for the other arguments apart from the one provided below. i want to make it work. please help

  **Your code so far**


function dropElements(arr, func) {
var array=[];
array.push(arr.filter(func))
  console.log(array)
return arr.slice(arr.indexOf(array[0][0]), arr.length)
}

console.log(dropElements([1, 2, 3], function(n) {return n > 3; }));

  **Your browser information:**

User Agent is: Mozilla/5.0 (Linux; U; Android 7.0; TECNO P701 Build/NRD90M; wv) AppleWebKit/537.36 (KHTML, like Gecko) Version/4.0 Chrome/88.0.4324.181 Mobile Safari/537.36 OPR/54.0.2254.56148.

Challenge: Drop it

Link to the challenge:

3

Why push the result of the filter into an array instead of just a normal variable?

There’s an array method that will find the first element that matches some condition, by the way.

4

I used an if… else statement and it didn’t work

5

it won’t affect the outcome, will it?

6

Probably not, but it makes it much harder to read and debug your logic.

function addTwo(a, b) {
  return a + b;
}

function addTwoComplex(a, b) {
  let values = [[a], [b]];
  return values.reduce((sum, val) => val[0] + sum, 0);
}

Both of these functions add together a and b. The second is unnecessarily complex and hard to reason about.

7

i understand. infact the if…else syatement that refused to work, worked perfectly when i removed the push() syntax.

8

thank you everyone, this is how my code look like and it works. every contribution help.

9 
function dropElements(arr, func) {
  var array = arr.filter(func);
  if (array == 0) { // what happens if you use !array here instead of array == 0?
    return []
  } else {
    return arr.slice(arr.indexOf(array[0]), arr.length)
  }
}

Nice work! I added one small comment for you to consider.

1 Like
10

It works fine. Thank you @JeremyLT

1 Like
11

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