Learn Algorithm Design by Building a Shortest Path Algorithm - Step 23

Tell us what’s happening:

I am setting the node inside the dictionary to zero, but its still not working

Your code so far

my_graph = {
    'A': [('B', 3), ('D', 1)],
    'B': [('A', 3), ('C', 4)],
    'C': [('B', 4), ('D', 7)],
    'D': [('A', 1), ('C', 7)]
}


/* User Editable Region */

def shortest_path(graph, start):
    unvisited = []
    distances = {}
    for node in graph:
        unvisited.append(node)
        if node == start:
            distances = {node: 0}

/* User Editable Region */

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Challenge Information:

Learn Algorithm Design by Building a Shortest Path Algorithm - Step 23

Hello Iswoboda!

You are very close, but that’s not how we set 0 to a list.
Its very similar to how you would get a character out of a string. You’re very close though!
You only have to adjust the part after distances.

1 Like

I tried changing the colon to a comma, and putting the zero in quotes, but this doesn’t work. Any other ways?

As a hint if I wanted to change a specific node I would do so by using distances[specific_node] = #whatever you wante to change it to.
So you will have to adjust that to make sure the current node is set to 0. Your logic is there, but the formatting wasn’t yet, hope this helps.

1 Like

Hi,

Think of it like you want to take the values in the variable node and assign it a value of zero.

Your code should look like the one below.
distances[your_variable] = assigned value

1 Like

reading the comments it should look like this but the code still doesnt pass

–solution removed—

Hi, please open a new topic for help on this, thanks!

Your code does look correct. Make sure it’s indented correctly in relation to the rest of the function?

If you have a question about a specific challenge as it relates to your written code for that challenge and need some help, click the Ask for Help button located on the challenge (it looks like a question mark). This button only appears if you have tried to submit an answer at least three times.

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Thank you.