Learn Algorithm Design by Building a Shortest Path Algorithm - Step 50

Python
1

Tell us what’s happening:

I’m trying to add a condition in my nested if statement and combine it with what I already have using the and operator but I’m not sure how to check that paths[node] is not empty. Any hints?

Your code so far

my_graph = {
    'A': [('B', 3), ('D', 1)],
    'B': [('A', 3), ('C', 4)],
    'C': [('B', 4), ('D', 7)],
    'D': [('A', 1), ('C', 7)]
}

def shortest_path(graph, start):
    unvisited = list(graph)
    distances = {node: 0 if node == start else float('inf') for node in graph}
    paths = {node: [] for node in graph}
    paths[start].append(start)
    
    while unvisited:
        current = min(unvisited, key=distances.get)
        for node, distance in graph[current]:
            if distance + distances[current] < distances[node]:
                distances[node] = distance + distances[current]

# User Editable Region

                if paths[node] != [] and paths[node][-1] == node:
                    paths[node] = paths[current]

# User Editable Region

                else:
                    paths[node].extend(paths[current])
                paths[node].append(node)
        unvisited.remove(current)
    
    print(f'Unvisited: {unvisited}\nDistances: {distances}\nPaths: {paths}')
    
#shortest_path(my_graph, 'A')

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Challenge Information:

Learn Algorithm Design by Building a Shortest Path Algorithm - Step 50

2

Hi @isabellamora4

Try checking if it is truthy.

Happ coding

3

that would check if it is true. i’m trying to check if it is empty

4

If it is empty it’s falsy.

6

It is great that you solved the challenge, but instead of posting your full working solution, it is best to stay focused on answering the original poster’s question(s) and help guide them with hints and suggestions to solve their own issues with the challenge.

We are trying to cut back on the number of spoiler solutions found on the forum and instead focus on helping other campers with their questions and definitely not posting full working solutions.