Learn Algorithm Design by Building a Shortest Path Algorithm - Step 52

Tell us what’s happening: Could you help me with that please?

Describe your issue in detail here.
They ask me to return(distances, paths) i have done that but my code doesn’t work. How could you help me please.

Your code so far

my_graph = {
    'A': [('B', 3), ('D', 1)],
    'B': [('A', 3), ('C', 4)],
    'C': [('B', 4), ('D', 7)],
    'D': [('A', 1), ('C', 7)]

def shortest_path(graph, start, target = ''):
    unvisited = list(graph)
    distances = {node: 0 if node == start else float('inf') for node in graph}
    paths = {node: [] for node in graph}
    while unvisited:
        current = min(unvisited, key=distances.get)
        for node, distance in graph[current]:
            if distance + distances[current] < distances[node]:
                distances[node] = distance + distances[current]
                if paths[node] and paths[node][-1] == node:
                    paths[node] = paths[current][:]

# User Editable Region

    targets_to_print = [target] if target else graph
    for node in targets_to_print:
        if node == start:
        print(f'\n{start}-{node} distance: {distances[node]}\nPath: {" -> ".join(paths[node])}') 
shortest_path(my_graph, 'A')
return(distances, paths)

# User Editable Region

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Challenge Information:

Learn Algorithm Design by Building a Shortest Path Algorithm - Step 52

You appear to have created this post without editing the template. Please edit your post to Tell us what’s happening in your own words.

Although I think the parentheses might be valid syntax, they are not required here.

You will need a space after “return” as well :+1: