Tell us what’s happening:
Can someone walk through the logic of this function? This one was brutal for me. Does anyone know if there exists an official FCC video that steps through what is happening across each line of this function?
I certainly got lost with all of the indexing and “neighbor node” and “current node”, etc. I am hoping a video exists of someone explaining the theory. Thanks!
Thanks in advance!
Your code so far
# User Editable Region
my_graph = {
'A': [('B', 5), ('C', 3), ('E', 11)],
'B': [('A', 5), ('C', 1), ('F', 2)],
'C': [('A', 3), ('B', 1), ('D', 1), ('E', 5)],
'D': [('C',1 ), ('E', 9), ('F', 3)],
'E': [('A', 11), ('C', 5), ('D', 9)],
'F': [('B', 2), ('D', 3)]
}
def shortest_path(graph, start, target = ''):
unvisited = list(graph)
distances = {node: 0 if node == start else float('inf') for node in graph}
paths = {node: [] for node in graph}
paths[start].append(start)
while unvisited:
current = min(unvisited, key=distances.get)
for node, distance in graph[current]:
if distance + distances[current] < distances[node]:
distances[node] = distance + distances[current]
if paths[node] and paths[node][-1] == node:
paths[node] = paths[current][:]
else:
paths[node].extend(paths[current])
paths[node].append(node)
unvisited.remove(current)
targets_to_print = [target] if target else graph
for node in targets_to_print:
if node == start:
continue
print(f'\n{start}-{node} distance: {distances[node]}\nPath: {" -> ".join(paths[node])}')
return distances, paths
shortest_path(my_graph, 'A')
# User Editable Region
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Challenge Information:
Learn Algorithm Design by Building a Shortest Path Algorithm - Step 59