Learn Basic JavaScript by Building a Role Playing Game - Step 157

JavaScript
1

We don’t want a player’s only weapon to break. The logical AND operator checks if two statements are true.

Use the logical AND operator && to add a second condition to your if statement. The player’s weapon should only break if inventory.length does not equal (!==) one.

Please I’m stuck here:
if (isMonsterHit() && inventory.length !== 1) {}
This is what i did and it didnt pass

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Learn Basic JavaScript by Building a Role Playing Game - Step 157

2

I don’t think the first condition in your if statement is complete. The second condition is okay though. send your complete code

3

Hello!

Correct syntax, wrong if condition. Look for the one that describes the player’s weapon breaking and modify the condition there.

4

Here is the complete code. I updated the logical and operator in the if condition. i cant seem to find the first condition.

health -= getMonsterAttackValue(monsters[fighting].level);
if (isMonsterHit() && inventory.length !== one) {
monsterHealth -= weapons[currentWeapon].power + Math.floor(Math.random() * xp) + 1 ;

5

one is no data type, you will get an undefined when you try this. You are comparing to data type number. You also are still in the wrong if statement there is one down below describing the weapon breaking…

6

This time I am really stuck. Please help!

Step 157

We don’t want a player’s only weapon to break. The logical AND operator checks if two statements are true.

Use the logical AND operator && to add a second condition to your if statement. The player’s weapon should only break if inventory.length does not equal (!==) one.

Here’s my code:

if (Math.random() <= .1 && inventory.length != 1) {
text.innerText += " Your " + inventory.pop() + " breaks.";
currentWeapon–;

}

7

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