Learn Basic String and Array Methods by Building a Music Player - Step 59

JavaScript
1

Tell us what’s happening:

Step 59

Use the setAttribute method on the playButton element to set an attribute named aria-label. For the value, use a ternary to set song?.title to Play ${song.title} or "Play" if there’s no song.title available.

Don’t forget you need template interpolation here, so you need to use backticks.

I cannot think any resolution. Please, help.

Your code so far

const setPlayButtonAccessibleText = () => {
const song = userData?.currentSong || userData?.songs[0];
playButton.setAttribute(“aria-label”, song?.title ? Play ${song.title} : Play);
};

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Challenge Information:

Learn Basic String and Array Methods by Building a Music Player - Step 59

1 Like
2

You might be affected by the bug that’s present in test on this step. Make sure the Play in the else of the ternary operator is within double quotes.

2 Likes
3

Still nothing.
playButton.setAttribute(“aria-label”, song?.title ? Play ${song.title} : "Play");

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4

There is an issue in this lesson. The suggestions are also wrong, it says to use a back slash \ but that does not work.

My answer:

  playButton.setAttribute("aria-label", `song?.title ? \`Play ${song.title}` : "Play"`);

The suggestion(is wrong) :

 song?.title ? \Play ${song.title}` : "Play"`

The Correct way:

  playButton.setAttribute("aria-label", song?.title ? `Play ${song.title}` : "Play");
5

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