Learn Basic String and Array Methods by Building a Music Player - Step 61

JavaScript
1

Tell us what’s happening:

Use a ternary operator to check if currentTitle is truthy. If so, implicitly return currentTitle otherwise implicitly return an empty string. Assign this result to playingSong.textContent.

Then, use a ternary operator to check if currentArtist is truthy. If so, implicitly return currentArtist otherwise implicitly return an empty string. Assign this result to songArtist.textContent.

I have tried but the code is not passing here for this

Your code so far

playingSong.textContent=currentTitle?(".currenTitle"):true
  songArtist.textContent=currentArtist?(".currentArtist"):true

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Challenge Information:

Learn Basic String and Array Methods by Building a Music Player - Step 61

2

Here is an example use of the ternary operator:

let a = b < c ? d : e

This is the equivalent of:

if (b <  c) {
  a = d
}
else {
  a = e
}

Hope this helps

3

playingSong.textContent = currentTitle ? currentTitle : “”;
songArtist.textContent = currentArtist ? currentArtist : “”;

Your code can be simplified. Good Luck

4 
playingSong.textContent=currentTitle?currenTitle:"true"
  songArtist.textContent=currentArtist?currentArtist:"true"

like so still not passing
ou should use the ternary operator to set the textContent property of playingSong to currentTitle or "" .

5

like so? still not passing

You should use the ternary operator to set the textContent property of playingSong to currentTitle or "".
6

You are so close

If it’s not truthy, what should you return?

7

you’re so close, you should return empty string

8

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