Learn Classes and Objects by Building a Sudoku Solver - Step 25

Python
1

Tell us what’s happening:

def valid_in_row(self, row, num):
pass
Replace pass with an expression that checks if the number num is not already present in that row.

I tried solving this with the method below but it didnt work, I need help please.
def valid_in_row(self, row, num):
if num not in self.board[row]:
return True

Your code so far

class Board:
    def __init__(self, board):
        self.board = board

    def find_empty_cell(self):
        for row, contents in enumerate(self.board):
            try:
                col = contents.index(0)
                return row, col
            except ValueError:
                pass
        return None

# User Editable Region

    def valid_in_row(self, row, num):
        if num not in self.board[row]:
           return True
        else:
           return False
        

# User Editable Region

puzzle = [
  [0, 0, 2, 0, 0, 8, 0, 0, 0],
  [0, 0, 0, 0, 0, 3, 7, 6, 2],
  [4, 3, 0, 0, 0, 0, 8, 0, 0],
  [0, 5, 0, 0, 3, 0, 0, 9, 0],
  [0, 4, 0, 0, 0, 0, 0, 2, 6],
  [0, 0, 0, 4, 6, 7, 0, 0, 0],
  [0, 8, 6, 7, 0, 4, 0, 0, 0],
  [0, 0, 0, 5, 1, 9, 0, 0, 8],
  [1, 7, 0, 0, 0, 6, 0, 0, 5]
]

gameboard = Board(puzzle)

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/126.0.0.0 Safari/537.36

Challenge Information:

Learn Classes and Objects by Building a Sudoku Solver - Step 25

2

Tests in this step expects a bit literal following of the instructions, parts that will make function fully functional will be added later.

3

This topic was automatically closed 182 days after the last reply. New replies are no longer allowed.