Learn Functional Programming by Building a Spreadsheet - Step 100

JavaScript
1

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Hello everyone,
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const spreadsheetFunctions = {
sum,
average,
median,
even: nums => nums.filter(isEven),
someeven: nums => nums.some(isEven),
everyeven: nums => nums.every(isEven),
firsttwo: nums => nums.slice(0, 2),
lasttwo: nums => nums.slice(-2),
has2: nums => nums.includes(2),
increment: nums => nums.map(num => num + 1),
random: ([x, y]) => Math.floor(Math.random() * y + x),
range: (start, end) => Array(end - start + 1).fill(start).map((element, index) => element + index),
}

console.log(spreadsheetFunctions.range(1, 5)) // output [ 1, 2, 3, 4, 5 ]

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Challenge Information:

Learn Functional Programming by Building a Spreadsheet - Step 100

2

where is the problem.?

3

coder99,
Thanks for your question. Problem is code does not pass.

4

your range property should have a nums with arrow function then pass nums as a spread operator in range its not that long and complex that u have made it

5

coder99,
Thanks your reply. I thought we need two arguments not just a spread operator of nums passing to the created range function.
Kindly explain

6

nums arrow function then range pass nums using spread operator

7

const spreadsheetFunctions = {
sum,
average,
median,
even: nums => nums.filter(isEven),
someeven: nums => nums.some(isEven),
everyeven: nums => nums.every(isEven),
firsttwo: nums => nums.slice(0, 2),
lasttwo: nums => nums.slice(-2),
has2: nums => nums.includes(2),
increment: nums => nums.map(num => num + 1),
random: ([x, y]) => Math.floor(Math.random() * y + x),
range: nums => range(…nums)
}

Thank you for your help.

2 Likes
8

hi! do you mind explaining why spreading the nums array work when the range function defined requires two parameters (start and end)?

9

Hi,
As much as I know, spread operaor allows us to expand elements of an iterable (like an array or string) or object properties into places where multiple elements or properties are expected .

10

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