Learn Introductory JavaScript by Building a Pyramid Generator - Step 108

Tell us what’s happening:

How can l use an if statement to check if inverted is true?

Your code so far

const character = "#";
const count = 8;
const rows = [];
let inverted = true;

function padRow(rowNumber, rowCount) {
  return " ".repeat(rowCount - rowNumber) + character.repeat(2 * rowNumber - 1) + " ".repeat(rowCount - rowNumber);
}

// TODO: use a different type of loop

// User Editable Region

for (let i = 1; i <= count; i++) {
  // run code if inverted is true
  rows.unshift(padRow(i, count));
}

// User Editable Region


/*while (rows.length < count) {
  rows.push(padRow(rows.length + 1, count));
}*/

/*for (let i = count; i > 0; i--) {
  rows.push(padRow(i, count));
}*/

let result = ""

for (const row of rows) {
  result = result + "\n" + row;
}

console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:126.0) Gecko/20100101 Firefox/126.0

Challenge Information:

Learn Introductory JavaScript by Building a Pyramid Generator - Step 108

By using it as the condition for the if statement.

Example:

let isSignedIn = true;

if(isSignedIn){
  console.log("You're already signed in!");
}else{
  console.log("Create a new account!");
}

You don’t need to use the equality operator == because isSignedIn variable will evaluate as a truthy value in your condition.

MDN: Truthy values
MDN: Falsy values

thank you, it passed