Learn Introductory JavaScript by Building a Pyramid Generator - Step 53

JavaScript
1

Tell us what’s happening:

I cant understand how to return a function using a parameter

Your code so far

const character = "#";
const count = 8;
const rows = [];


// User Editable Region

function padRow(name) {
  return "Hello!";
}

// User Editable Region

const call = padRow();
console.log(call);


for (let i = 0; i < count; i = i + 1) {
  rows.push(character.repeat(i + 1))
}

let result = ""

for (const row of rows) {
  result = result + "\n" + row;
}

console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/126.0.0.0 Safari/537.36

Challenge Information:

Learn Introductory JavaScript by Building a Pyramid Generator - Step 53

2

Hi there,

function padRow(name) {
  return "Hello!";
}

The original function above will always return "Hello!" with whatever name parameter value:

padRow("John")

will return "Hello!"

padRow("Alice")

will return "Hello!"

Now, we need to change the padRow function so:

padRow("John")

will return "John"

padRow("Alice")

will return "Alice"

To do so, the instruction gives us a hint:

Change your padRow function to return the name parameter directly.

That means:
instead of return the string "Hello!",
we return the parameter name