Learn Introductory JavaScript by Building a Pyramid Generator - Step 58

JavaScript
1

Tell us what’s happening:

Your function should declare a “test” variable.

I am soooooooooooo losttttttttttttttttttttttttt.

java unfortunately is entirely diff from html :sleepy:

Your code so far

const character = "#";
const count = 8;
const rows = [];


// User Editable Region

function padRow(name) {
const test = padRow("Testing");
  return character + name;
}
console.log(test);

// User Editable Region

const call = padRow("CamperChan");
console.log(call);


for (let i = 0; i < count; i = i + 1) {
  rows.push(character.repeat(i + 1))
}

let result = ""

for (const row of rows) {
  result = result + "\n" + row;
}

console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/128.0.0.0 Safari/537.36

Challenge Information:

Learn Introductory JavaScript by Building a Pyramid Generator - Step 58

2

this is not Java, this is JavaScript

for your code, let’s see

you need to assing the string Testing to test, not a call to padRow

3

My bad, javascript.

Like this?

function padRow(name) {
const test = Testing;
  return character + name;
}
console.log(test);
4

a string requirs quotes, that’s not a string

5

Even with the quotation mark it’s not working.

It keeps on saying " Your function should declare a test variable."

6

what’s your code now?

7

This;

function padRow(name) {
const test = "Testing";
  return character + name;
}
console.log(test);
8

this one gives you an error, you should remove this

9

Done, thanks

i also had to reset the lesson

10

lol

i must have overlooked this instruction" Remove that console.log to pass the tests and continue"