# Learn Introductory JavaScript by Building a Pyramid Generator - Step 99

### Tell us what’s happening:

I dont what is wrong in here i alread shifted the the first value on the array and printed that avariable

### Your code so far

``````const character = "#";
const count = 8;
const rows = [];

function padRow(rowNumber, rowCount) {
return " ".repeat(rowCount - rowNumber) + character.repeat(2 * rowNumber - 1) + " ".repeat(rowCount - rowNumber);
}

// TODO: use a different type of loop
/*for (let i = 1; i <= count; i++) {
rows.push(padRow(i, count));
}*/

/*while (rows.length < count) {
rows.push(padRow(rows.length + 1, count));
}*/

/*for (let i = count; i > 0; i--) {
rows.push(padRow(i, count));
}*/

// User Editable Region

const numbers = [1, 2, 3];

const unshifted= numbers.unshift(5);
console.log(numbers);
console.log(unshifted)

const shifted = numbers.shift();
console.log(shifted)
console.log(numbers)

// User Editable Region

let result = ""

for (const row of rows) {
result = result + "\n" + row;
}

console.log(result);
``````

### Your browser information:

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/125.0.0.0 Safari/537.36`

### Challenge Information:

Learn Introductory JavaScript by Building a Pyramid Generator - Step 99

you have duplicate console log in your code. you need to add new console for your newly created variable.

instructions:
Declare a `shifted` variable, assign it the result of calling `.shift()` on your `numbers` array, and print the variable.
starting code:

``````const numbers = [1, 2, 3];

const unshifted = numbers.unshift(5);
console.log(unshifted);
console.log(numbers);
``````