Learn Recursion by Building a Decimal to Binary Converter - Step 12

JavaScript
1

I am struggling with the NEW and final part of this step, " Also, as we mentioned in step 1 that we are considering only positive numbers, we should add a third condition in IF statement to check whether the number is less than 0 (i.e negative numbers)"…

My code so far looks like this:

if (!numberInput.value || isNaN(parseInt(numberInput.value))) {

  }

I have tried the following so far:

if (!numberInput.value || isNaN(parseInt(numberInput.value)) || numberInput.value < 0) {}
if (!numberInput.value || isNaN(parseInt(numberInput.value)) || (parseInt(numberInput.value < 0)) { }

Each time i get the same prompt back: You should wrap the value returned by parseInt() in the isNaN() function. And add a third condition which checks the value returned by parseInt() to be less than 0.

Please let me know how I can pass this step and what I’m doing wrong!

2

If you have a question about a specific challenge as it relates to your written code for that challenge and need some help, click the Ask for Help button located on the challenge (it looks like a question mark). This button only appears if you have tried to submit an answer at least three times.

The Ask for Help button will create a new topic with all code you have written and include a link to the challenge also. You will still be able to ask any questions in the post before submitting it to the forum.

Thank you.

3

That being said, as far as the third condition goes, you only need to wrap numberInput.value in parseInt so we know that value is a number.