Learn Regular Expressions by Building a Password Generator - Step 61

Python
1

Tell us what’s happening:

it is telling me i should have break inside the new if body. What is wrong with this?

Your code so far

import re
import secrets
import string


def generate_password(length, nums, special_chars, uppercase, lowercase):
    # Define the possible characters for the password
    letters = string.ascii_letters
    digits = string.digits
    symbols = string.punctuation

    # Combine all characters
    all_characters = letters + digits + symbols

    while True:
        password = ''
        # Generate password
        for _ in range(length):
            password += secrets.choice(all_characters)
       
        constraints = [
            (nums, r'\d'),
            (lowercase, r'[a-z]'),
            (uppercase, r'[A-Z]'),            
            (special_chars, fr'[{symbols}]')            
        ]

        # Check constraints
        count = 0

# User Editable Region

        if [constraint <= len(re.findall(pattern, password)) for constraint, pattern in constraints]:
            break

# User Editable Region

    return password

# new_password = generate_password(8)
# print(new_password)

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Challenge Information:

Learn Regular Expressions by Building a Password Generator - Step 61

2

For the if condition, use a call to the all() function and pass an empty list as the argument to the function call.

3

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