Learn Regular Expressions by Building a Password Generator - Step 61

Python
1

Tell us what’s happening:

“You should have break inside your new if body” . I can’t fix this problem.

Your code so far

import re
import secrets
import string


def generate_password(length, nums, special_chars, uppercase, lowercase):
    # Define the possible characters for the password
    letters = string.ascii_letters
    digits = string.digits
    symbols = string.punctuation

    # Combine all characters
    all_characters = letters + digits + symbols

    while True:
        password = ''
        # Generate password
        for _ in range(length):
            password += secrets.choice(all_characters)
       
        constraints = [
            (nums, r'\d'),
            (lowercase, r'[a-z]'),
            (uppercase, r'[A-Z]'),            
            (special_chars, fr'[{symbols}]')            
        ]

        # Check constraints
        count = 0

# User Editable Region

        if [constraint <= len(re.findall(pattern, password)) for constraint, pattern in constraints]:

# User Editable Region

            break

    return password

# new_password = generate_password(8)
# print(new_password)

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/124.0.0.0 Safari/537.36

Challenge Information:

Learn Regular Expressions by Building a Password Generator - Step 61

2

For the if condition, use a call to the all() function and pass an empty list as the argument to the function call.

Did you try this part?

1 Like
3

if all([constraint <= len(re.findall(pattern, password)) for constraint, pattern in constraints]):
break

It also does not work

4

Try this?

pass an empty list as the argument to the function call (all())

5

This topic was automatically closed 182 days after the last reply. New replies are no longer allowed.