Learn Regular Expressions by Building a Password Generator - Step 72

I have tried this for a while:

You should have an if statement that checks if name == ‘main’.

My code so far

import re
import secrets
import string


def generate_password(length=16, nums=1, special_chars=1, uppercase=1, lowercase=1):

    # Define the possible characters for the password
    letters = string.ascii_letters
    digits = string.digits
    symbols = string.punctuation

    # Combine all characters
    all_characters = letters + digits + symbols

    while True:
        password = ''
        # Generate password
        for _ in range(length):
            password += secrets.choice(all_characters)
        
        constraints = [
            (nums, r'\d'),
            (special_chars, fr'[{symbols}]'),
            (uppercase, r'[A-Z]'),
            (lowercase, r'[a-z]')
        ]

        # Check constraints        
        if all(
            constraint <= len(re.findall(pattern, password))
            for constraint, pattern in constraints
        ):
            break
    
    return password
    

# User Editable Region

new_password = generate_password()
print('Generated password:', new_password)
if __name__ == '__main__'


# User Editable Region

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Challenge Information:

Learn Regular Expressions by Building a Password Generator - Step 72

The request says:

Finally, put the last two lines of your code inside an if statement that execute when __name__ == '__main__'

You have your if statement after the two lines. Also your condition is missing the :
An if is a block. Anything within the if requires indentation.

Thank you i got it! Thanks!

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