Learn Special Methods by Building a Vector Space - Step 47

Tell us what’s happening:

im confused, instructions tell me to modify variable v2 and put x = 0.5 and y = 1.25, i’ve done that no?

Your code so far

class R2Vector:
    def __init__(self, *, x, y):
        self.x = x
        self.y = y

    def norm(self):
        return sum(val**2 for val in vars(self).values())**0.5

    def __str__(self):
        return str(tuple(getattr(self, i) for i in vars(self)))

    def __repr__(self):
        arg_list = [f'{key}={val}' for key, val in vars(self).items()]
        args = ', '.join(arg_list)
        return f'{self.__class__.__name__}({args})'

    def __add__(self, other):
        if type(self) != type(other):
            return NotImplemented
        kwargs = {i: getattr(self, i) + getattr(other, i) for i in vars(self)}
        return self.__class__(**kwargs)

    def __sub__(self, other):
        if type(self) != type(other):
            return NotImplemented
        kwargs = {i: getattr(self, i) - getattr(other, i) for i in vars(self)}
        return self.__class__(**kwargs)

class R3Vector(R2Vector):
    def __init__(self, *, x, y, z):
        super().__init__(x=x, y=y)
        self.z = z

# User Editable Region

v1 = R2Vector(x=2, y=3)
v2 = R3Vector(x=2, y=2, z=3)
print(f'v1 = {v1}')
print(R2Vector(x=0.5, y=1.25))


# User Editable Region

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Challenge Information:

Learn Special Methods by Building a Vector Space - Step 47

Hi @Mr.Merati

Modify your v2 variable assignment to be an R2Vector instance having x=0.5 and y=1.25 .

You should modify your v2 variable assignment to be an R2Vector instance having x=0.5 and y=1.25 .

Your code has modified the print call, not the v2 variable.

Happy coding

wow my mind must of been cooked tbh i do just wake up and code so it was