Tell us what’s happening:
Describe your issue in detail here.
Your code so far
/* User Editable Region */
text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
index = alphabet.find(text[0].lower())
shifted = (index + shift)
shifted_letter = alphabet [shifted]
/* User Editable Region */
Your browser information:
User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/119.0.0.0 Safari/537.36 OPR/105.0.0.0
Challenge Information:
Learn String Manipulation by Building a Cipher - Step 16
system
2
You appear to have created this post without editing the template. Please edit your post to Tell us what’s happening in your own words.
I don’t think you can have a space between alphabet
and [shifted]
Declare a variable named shifted
and assign it the alphabet
letter at index
plus shift
.
I like that you split this up into 2 operations, adding index+shift and then assigning the letter. Makes it very clear.
However, to pass the test I think you will need to do this in 1 line. You can perform the index+shift operation within the [square brackets]
system
Closed
4
This topic was automatically closed 182 days after the last reply. New replies are no longer allowed.