Learn String Manipulation by Building a Cipher - Step 30

Tell us what’s happening:

something wrong? i i’ve tried to use text[0] = ‘car’ for this solution.

Your code so far


# User Editable Region

text ='Hello World'
text[0] ='car'

# User Editable Region

shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'

for char in text.lower():
    index = alphabet.find(char)
    print(char, index)
    new_index = index + shift

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/127.0.0.0 Safari/537.36

Challenge Information:

Learn String Manipulation by Building a Cipher - Step 30

Yes actually. You see think of the phrase “Hello world” as a list of letters with the ‘H’ in position zero and ‘e’ in position 1 and so forth. The list assumes that each position holds a single letter (or punctuation mark or space or number). The code doesn’t know how to handle you shoving three letters into a spot where there once was one.

Happy coding. :slight_smile:

1 Like

a character of your choice

Instructions are explicit here, a “character” is 1 letter.

finally, thank you so much!