Learn String Manipulation by Building a Cipher - Step 37

Python
1

Tell us what’s happening:

I am getting an error on Step 37. I have tried various versions of the print(char == “”) step. I have tried it with spaces, without spaces, with single quotes, with double quotes, etc.

Your code so far


/* User Editable Region */

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    print(char == "")
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

/* User Editable Region */

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 37

2

you want to check if char is equal to a space, not an empty string

3

I don’t know what you mean. Would you please explain.

4

space " " is different from empty string "", the difference is a space

5

I just figured it out. Thank you.

1 Like
6

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