Learn String Manipulation by Building a Cipher - Step 42

Python
1

Tell us what’s happening:

Describe your issue in detail here.
I don’t understand my mistake. Task says that: “The condition of this if statement should evaluate to True if char is an empty space and False otherwise. Inside the if body, print the string 'space!' . Remember to indent this line.”

Your code so far

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    if char == ' ': 
        print('space!')
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)


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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 42

2

You appear to have created this post without editing the template. Please edit your post to Tell us what’s happening in your own words.

4

it looks like you have a space after the colon here, it’s not a syntax error, but the tests have a few issues still that need to be fixed, please remove the space

5

Thanks for help, but it says that the mistake is that I didn’t print ‘space!’

6

yes, the space after the colon in the if statement is making so that the tests are not finding the if statement and the code that is inside (your print), so please remove the space after the colon

7

text = ‘Hello World’
shift = 3
alphabet = ‘abcdefghijklmnopqrstuvwxyz’
encrypted_text = ‘’

for char in text.lower():
if char==’ ':print(‘space!’)
index = alphabet.find(char)
new_index = index + shift
encrypted_text += alphabet[new_index]
print(‘char:’, char, ‘encrypted text:’, encrypted_text)

Please tell what is wrong here?

8

Please open a new topic for your question, thanks!

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Thank you.

9

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