Learn String Manipulation by Building a Cipher - Step 62

Python
1

Tell us what’s happening:

Im uncertain if the code is correct here, any suggestions? its giving me errors

Your code so far


text = 'Hello Zaira'
custom_key = 'python'

def vigenere(message, key):
    key_index = 0
    alphabet = 'abcdefghijklmnopqrstuvwxyz'
    encrypted_text = ''

    for char in message.lower():

# User Editable Region

        # Append space to the message
        if char == ' ':
            encrypted_text += char
        else: 
             key_char = key[key_index % len(key)], key_index += 1

# User Editable Region

            index = alphabet.find(char)
            new_index = (index + offset) % len(alphabet)
            encrypted_text += alphabet[new_index]
    print('plain text:', message)
    print('encrypted text:', encrypted_text)

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 62

2

What error are you getting? This should indicate where your error is

3

You have inconsistent indentation here:

Screenshot 2024-05-13 084305

4

still doesnt pass the code

5

Please share your updated code and any errors you are getting, thanks!

6

Append space to the message

    if char == ' ':
        encrypted_text += char
    else: 
     key_char = key[key_index % len(key)], key_index += 1

Im getting a syntax error

7

You still have inconsistent indentation

Screenshot 2024-05-13 103401

When you indent keep everything the same. Four spaces, or just press tab once. The line below if and the line below else need to be indented the same amount. They need to have exactly the same amount of spaces.

8 
    # Append space to the message
    if char == ' ':
        encrypted_text += char
    else:
       key_char = key[key_index % len(key)], key_index += 1

am i still doing it wrong…?

9

yes, it’s still wrong

if this:
    code code
else:
    code code
10

Just indent these lines the same amount of spaces

11

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