Learn String Manipulation by Building a Cipher - Step 67

Python
1

Tell us what’s happening:

Is the code I wrote an indentation problem? The variable calling the the function is here and the return statement within the og function. Where’s the problem?

Your code so far

text = 'Hello Zaira'
custom_key = 'python'

def vigenere(message, key):
    key_index = 0
    alphabet = 'abcdefghijklmnopqrstuvwxyz'
    encrypted_text = ''

    for char in message.lower():
    
        # Append space to the message
        if char == ' ':
            encrypted_text += char
        else:        
            # Find the right key character to encode
            key_char = key[key_index % len(key)]
            key_index += 1

# User Editable Region

            # Define the offset and the encrypted letter
            offset = alphabet.index(key_char)
            index = alphabet.find(char)
            new_index = (index + offset) % len(alphabet)
            encrypted_text += alphabet[new_index]
            return encrypted_text

encryption = vigenere(text, custom_key)

# User Editable Region

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/126.0.0.0 Safari/537.36

Challenge Information:

Learn String Manipulation by Building a Cipher - Step 67

2

Yes, it is an indentation problem. Currently, your return is nested inside an else, which is inside the for loop. It should be outside the loop.

1 Like
3

This topic was automatically closed 182 days after the last reply. New replies are no longer allowed.