Learn the Bisection Method by Finding the Square Root of a Number - Step 17

Tell us what’s happening:

You should create an if statement that checks if root is None.

Your code so far

def square_root_bisection(square_target, tolerance=1e-7, max_iterations=100):
    if square_target < 0:
        raise ValueError('Square root of negative number is not defined in real numbers')
    if square_target == 1:
        root = 1
        print(f'The square root of {square_target} is 1')
    elif square_target == 0:
        root = 0
        print(f'The square root of {square_target} is 0')

    else:
        low = 0
        high = max(1, square_target)
        root = None
        
        for _ in range(max_iterations):
            mid = (low + high) / 2
            square_mid = mid**2

            if abs(square_mid - square_target) < tolerance:
                root = mid
                break

            elif square_mid < square_target:
                low = mid
            else:
                high = mid


# User Editable Region

    if root == None:
        print(f'Failed to converge within {max_iterations} iterations.')

# User Editable Region


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Challenge Information:

Learn the Bisection Method by Finding the Square Root of a Number - Step 17

too unindented, it needs to be after the for loop, so at the same level of the for loops, add four spaces to each line you added

Sorry, it is still not working. Same error. ’ You should create an if statement that checks if root is None

post your updated code please

You could also check this:

https://www.geeksforgeeks.org/difference-between-and-is-operator-in-python/

But if it’s still not working please share your updated code.

Tell us what’s happening:

I have changed the indentation, but still not working

Your code so far

def square_root_bisection(square_target, tolerance=1e-7, max_iterations=100):
    if square_target < 0:
        raise ValueError('Square root of negative number is not defined in real numbers')
    if square_target == 1:
        root = 1
        print(f'The square root of {square_target} is 1')
    elif square_target == 0:
        root = 0
        print(f'The square root of {square_target} is 0')

    else:
        low = 0
        high = max(1, square_target)
        root = None
        
        for _ in range(max_iterations):
            mid = (low + high) / 2
            square_mid = mid**2

            if abs(square_mid - square_target) < tolerance:
                root = mid
                break

            elif square_mid < square_target:
                low = mid
            else:
                high = mid


# User Editable Region

        if root == None:
            print(f'Failed to converge within {max_iterations} iterations.')

# User Editable Region


Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/125.0.0.0 Safari/537.36 Edg/125.0.0.0

Challenge Information:

Learn the Bisection Method by Finding the Square Root of a Number - Step 17

The hint say

You should create an if statement that checks if root is None .

It is telling you exactly what code you should use

Yes. I got it. Thank you

To be fair “is” has never been explained as a keyword, nor is it a keyword in most common languages.

In the future, please create your own topic when you have specific questions about your own challenge code. Only respond to another thread when you want to provide help to the original poster of the other thread or have follow up questions concerning other replies given to the original poster.

The easiest way to create a topic for help with your own solution is to click the Ask for Help button located on each challenge. This will automatically import your code in a readable format and pull in the challenge url while still allowing you to ask any question about the challenge or your code.

Thank you.

It is explained in step 10 of Binary Search Tree, you are right that here is not yet explained