Learn the Bisection Method by Finding the Square Root of a Number - Step 8

Python
1

Tell us what’s happening:

Don’t know how to code this part/request. Would love some help

Your code so far

def square_root_bisection(square_target, tolerance=1e-7, max_iterations=100):
    if square_target < 0:
        raise ValueError('Square root of negative number is not defined in real numbers')
    if square_target == 1:
        root = 1
        print(f'The square root of {square_target} is 1')
    elif square_target == 0:
        root = 0
        print(f'The square root of {square_target} is 0')

# User Editable Region

    else square_target > 1:
        pass

# User Editable Region

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Challenge Information:

Learn the Bisection Method by Finding the Square Root of a Number - Step 8

2

This is the step:

Step 8

Next, you are going to work on the cases where the square_target is a positive number apart from 1 or 0.

Create an else clause to handle these cases.

3

What specifically about the instructions is confusing? (In your words, not copy-pasting)

I don’t this looks like the example of else you were previously given?

4

Hey Jeremy, I’m having trouble figuring out the symbol that I need to equate square_target with a positive number other than 1 or 0

5

But does an else clause require a comparison? Or allow one?

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6

No, it does not require or allow.

7

I finally managed to find the right answer. Thanks Jeremy!

1 Like