Need help with this challenge, Basic JavaScript: Counting Cards

JavaScript
1

None of the tests I m performing for this problem is working. Could someone please tell me what I am doing wrong in this code? Am Ieven on a decent path to solving it correctly?

Here’s my solution:

var count = 0;

function cc(card) {
  // Only change code below this line
  if (count > 0){
    console.log(++count);
    return "count Bet";
  }else if(count < 0){
    console.log(--count);
    return "count Hold";
  }else(count===0)
    return "count Hold";
    }
  // Only change code above this line


// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');

Link to counting cards

3

You’re posting count to the comment log instead of returning the value and exiting the function.

4 
var count = 0;

function cc(card) {
  // Only change code below this line
  switch(card) {
    case 2:
    case 3:
    case 4:
    case 5:
    case 6:
      count += 1;
      break;
    case 7:
    case 8:
    case 9:
      count += 0;
      break;
    case 10:
    case "J":
    case "Q":
    case "K":
    case "A":
      count -= 1;
}

return count + (count > 0? "Bet" : "Hold");
  // Only change code above this line
}

// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');</p>

So, I followed along to the posted video to help me determine the logic of this problem:
Can someone please help me. I, for the life of me cannot understand the logic he’s using to run the card values at the bottom of the code i.e. : cc(3); . When he runs the bottom values through, if cc(3); increments by count +=1;, why is the card variable 2? Could someone explain this to me like a 4 year old?[Counting Cards, freeCodeCamp Basic Javascript] I don’t care about negative remarks I just want to understand this!!
(https://youtu.be/zgs06k00YIE)

I’m also having difficulty getting this to pass. Any reason why?

6

Around the 6:23 mark.

7

You got stuck there. I had same problem.

remember cc is the name of the function and we will get only two output. Bet or hold
if count is greater than zero , result is bet

if it is a negative value or 0(-1,-2,-3,-4 ,or 0) result is hold;

I think you feel difficulty to understand this is because you did not understand switch statement
I am not an expert. but i will try to implement this with if statement, then i will try to explain switch

var count=0;

function cc(card){

if(card===2||card===3||card===4||card===5||card===6){
/the count value is zero. when you pass value 2 or 3 4 or 5 or 6 count will be added by one
example
cc is the name of the function
what is the value of count now?
value of count is zero
now i invoke function
cc(2)
what is the value of count now?
one
because this condition is true
/
cc(3)
i invoke the function again
what is the value of count three
how many time this function satisfy this block of code condition as true , it add one by one
count++

}

else{ if(card===10||card===‘J’||card===‘Q’||card===‘K’||card===‘A’){

//same thing here instead of adding it will be subtract
count–

}

else{
//if cc(0) don’t add or subtract, keep the value same
//example
// cc(2) it satisfy the first condition so it added the count"s value by one
now value of count is 1
after that I invoke cc(0)
what is the value of count now:

one
then
if i invoke cc(‘A’)
value of count will be zer

count

}

}

var answer;

if(count;<=0){

//if count lessthan or equal to zero Hold

answer= ‘Hold’

}

else {
if count greater than zero Bet
answer=‘Bet’

}

console.log(count)

return answer;

}

//going to invoke function count (initial value of count is 0) answer
cc(2); count=count+1 =0+1=1 Bet
now value of count =1
cc(2); count=count+1 =1+1=2 Bet
now value of count =2
cc(3) count=count+1 =2+1=3 Bet

now value of count =3

cc(0) count=count+1 =2+1=3 Bet
now value of count same (3) we have not set any arithmetic operation when we invoke function with argument zero
value of count =3
cc(‘A’) count=count-1 =3-1=2 Bet
cc(‘A’) count=count-1 =2-1=1 Bet
cc(‘A’) count=count-1 =1-1=0 Hold
cc(‘A’) count=count-0 =0-1=-1 Hold

in switch statement ‘case’ we use instead of || in if statemen

for example
var value=1

function m(a,b){
if(a<value||b<value){
return value
}

}

in switch statement

var value=1
function m(a,b)

switch(value)

case a<value:
case b<value
return ’ did you understand ’
default :
return slight_smile: