Pairwise return smaller value

JavaScript
1

Tell us what’s happening:
pairwise([0, 0, 0, 0, 1, 1], 1) should return 10
Can anyone explain this result? I thought 0 and 1 can only be used once, so the answer is 4.

Your code so far

function pairwise(arr, arg) {
  
  var ind = 0;
  var indArr = [];
  for(var i = 0; i < arr.length; i++){
    for(var j = 0; j < arr.length; j++){
      if(i < j && arr[i] + arr[j] == arg && indArr.indexOf(arr[i]) < 0){
        
        indArr.push(arr[i]);
        indArr.push(arr[j]);
        
        ind += (i + j);
      }
    }
  }
  return ind;
}

pairwise([0, 0, 0, 0, 1, 1], 1);

Your browser information:

Your Browser User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.84 Safari/537.36.

Link to the challenge:

3

If multiple pairs are possible that have the same numeric elements but different indices, return the smallest sum of indices. Once an element has been used, it cannot be reused to pair with another.

my understanding is that 0 and 1 can only be used once and the smallest indices should be used. There is only one pair (0 and 1). the smallest indices for 0 is 0, for 1 is 4. so the result should be 4. How come it is 10?

5

Ok, I got you. Thank you so much!

6

Hey @camperextraordinaire,

I am still not convinced. The question mentions that…

If multiple pairs are possible that have the same numeric elements but different indices, return the smallest sum of indices.

… which in my opinion means that the pair [0, 1] with indices [0, 4] prevails when compared with the pair [0, 1] with indices [1, 5], meaning the final result should be 4 instead of 10, don’t you think?

Cheers,
Fm