# ParseInt Function with a Radix

Tell us what’s happening:

I have tried finding a solution with/out the radix. When I console.log with base 2, I am getting 19 but my test still returns an error like so;

``````function convertToInteger(str, radix) {
var parsed = parseInt(str, radix)
if (isNaN(parsed)) {
return NaN;
}
return parsed;
}

console.log(convertToInteger("10011", 2));

returns 19 before running the test.

and it returns this;

// running tests

convertToInteger("10011") should return 19

convertToInteger("111001") should return 57

// tests completed

after running the test.
``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:68.0) Gecko/20100101 Firefox/68.0`.

This is the function call done by the tests, only one argument

Your function has two parameters - so your radix is actually undefined

Anyway, you don’t need the part with NaN as `parseInt` returns NaN on its own if it can’t convert to a number

I have tried with one argument as well and I am getting nowhere. How do I get convertToInteger() to return 19 and 57.

NaN (`convertToInteger("JamesBond")` should return NaN) is one of the test required and it passes.

Its the two tests i.e. `convertToInteger("10011")` should return 19 and `convertToInteger("111001")` should return 57 that are not passing.

Look at this line, what should `radix` be? It can’t be a parameter of the function because the function calls in the tests have only one argument, so you need to actually put a value there instead of a variable

If you use `parseInt` correctly, it will return `NaN` on its own without needing other lines of code, as the value returned from `parseInt` would be `NaN`

yes i see what you say about NaN. Let me try var parsed = parseInt(str, radix)

parseInt() method will return NaN if string argument is not number so you don’t need to test the result.
about radix, either you put 2 as parameter in parseInt() method or create a var radix = 2

I put in a value and I got all my tests to pass. I can now move. Thanks,