Profile Lookup error

JavaScript
1

Tell us what’s happening:
"TypeError : cannot read property ‘0’ of undefined"
what does that mean what is wrong with my code?

Your code so far

//Setup
var contacts = [
    {
        "firstName": "Akira",
        "lastName": "Laine",
        "number": "0543236543",
        "likes": ["Pizza", "Coding", "Brownie Points"]
    },
    {
        "firstName": "Harry",
        "lastName": "Potter",
        "number": "0994372684",
        "likes": ["Hogwarts", "Magic", "Hagrid"]
    },
    {
        "firstName": "Sherlock",
        "lastName": "Holmes",
        "number": "0487345643",
        "likes": ["Intriguing Cases", "Violin"]
    },
    {
        "firstName": "Kristian",
        "lastName": "Vos",
        "number": "unknown",
        "likes": ["Javascript", "Gaming", "Foxes"]
    }
];


function lookUpProfile(firstName, prop){
// Only change code below this line

  for(var x = 0; x < contacts.length; x++){
      if(contacts.firstName[x] === firstName){
         if(contacts[x].hasOwnProperty(prop)){
            return contacts[x][prop];
          }else{
            return "No such property";
          }
      }
  }
  return "No such contact";
// Only change code above this line
}

// Change these values to test your function
lookUpProfile("Akira", "address");

Your browser information:

Your Browser User Agent is: Mozilla/5.0 (Linux; U; Android 4.2.1; en-gb; ME301T Build/JOP40D) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Safari/534.30.

Link to the challenge:

3

Probably this is what is causing it contacts.firstName[x] , because contacts.firstName is not an array, while contacts is , I notice that you are referring to it correctly below that line so it may just be a typo.

4

i dont understand what should i do then?

6

oh should i just write contacts[x] instead of contacts.firstName[x] because that is not working either

8

at this point i dont even know what my name means so no.

10

it says no such contact

12

yeah i did that exactly and it says no such contacts

13

now its giving the above error again

14

try

if (contacts[x].firstName === firstName){

if (contacts[x].hasOwnProperty(prop)){
  return contacts[x][prop];
16

I understand, but all that was doing was confusing him.