Profile Lookup (Help)

Curriculum Help
1

This first part should pass the first three tests, any ideas as to what I have done incorrectly? Thanks!

Your code so far


// Setup
var contacts = [
{
    "firstName": "Akira",
    "lastName": "Laine",
    "number": "0543236543",
    "likes": ["Pizza", "Coding", "Brownie Points"]
},
{
    "firstName": "Harry",
    "lastName": "Potter",
    "number": "0994372684",
    "likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
    "firstName": "Sherlock",
    "lastName": "Holmes",
    "number": "0487345643",
    "likes": ["Intriguing Cases", "Violin"]
},
{
    "firstName": "Kristian",
    "lastName": "Vos",
    "number": "unknown",
    "likes": ["JavaScript", "Gaming", "Foxes"]
}
];


function lookUpProfile(name, prop){
// Only change code below this line
for (var i=0; i < contacts.length; i++) {
if (name == "firstName" && contacts[name].hasOwnProperty(prop) == true) {
    return contacts[name][prop] = value;
}
}
// Only change code above this line
}

console.log(lookUpProfile("Akira", "likes"));

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.106 Safari/537.36.

Challenge: Profile Lookup

Link to the challenge:

2 
name == "firstName"

This checks if the name argument is the literal string ā€œfirstNameā€.

contacts[name]

contacts is an array, so you should access its values with a 0-based index. name is a string, not a number.

3

Hello~!

The very first thing I notice is that your if condition will never run, because the name parameter will not equal the string ā€œfirstNameā€. Were you trying to access the objectā€™s firstName property?

4

Here are some additional errors to address:

This will always be undefined. contacts is an array of objects, not an object.

Again, the bracket notation isnā€™t quite correct here. Additionally, value has not been declared or initialised and will throw an undefined error.

5

Yes, I was trying to see if the name passed was the firstName property, so Iā€™m just accessing everything wrong?

6

I was assuming it was because i was accessing it like that but what confuses me is that if I do use a zero based index like contact[0], wouldnā€™t it only check the first object within the array? For it to check the whole collection would it be like contact[0-3]? Which is probably incorrect

7

Youā€™ve got your loop index i, which corresponds to the indexes of the contacts array (because you initialize i to 0, and the terminal condition is i < contacts.length). You could access each contact in the array in turn by utilizing that i variable within the loop.

8

If you notice then you can see that ā€˜contactsā€™ is an array.
Arrays can only be accessed using numbers. For example: contacts[0] or contacts[1] etc.
You have tried to access the array by doing contacts[name].
This you can do if contacts is an object. But it is not. ā€˜nameā€™ is a variable. Hence your fucntion will not run.