Regex carat (^) symbol

Tell us what’s happening:

I’m confused. The ^ negates a character set, right?

So why does this solution call for /^(\d+)\s\1\s\1$/ ? Does the carat work differently here? How??

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Challenge: Reuse Patterns Using Capture Groups

Link to the challenge:

Yes, when used in a character set:

[^a-z] // not a-z

Yes, it is used at the beginning of the regex so it means to anchor the regex to the beginning of the string. In other words, no other characters can come before it.


“0…” matches.

“a0…” does not match.

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I see so it has a whole another use. Thanks!

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