Tell us what’s happening:
I have spent a full day and nearly all night trying to figure out how this algorithm works.

I just need a textual breakdown of how this algorithm outputs 5, for me 6 makes sense as it’s every number in the array -1 then added together, so 2-1, 3-1, 4-1, so 1+2+3. But that clearly isn’t the case, some one please help, I’m close to defeat!

Your code so far

function sum(arr, n) {
// Only change code below this line
if (n <= 0) {
return arr[0];
} else {
return sum(arr, n - 1) + arr[n];
}
// Only change code above this line
}
var total = sum([2, 3, 4], 1);
console.log(total)

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Your code has been blurred out to avoid spoiling a full working solution for other campers who may not yet want to see a complete solution. In the future, if you post a full passing solution to a challenge and have questions about it, please surround it with [spoiler] and [/spoiler] tags on the line above and below your solution code.

Thankyou so much for your reply, it was really helpful. Could you please review my comments at the bottom of my code here and tell me if I am understanding this correctly…?
Sorry about the spoiler, I have [spoiler] commented out my reply!
Thanks again.

function sum(arr, n) {
// Only change code below this line
if (n <= 0) {
return arr[0];
} else {
return sum(arr, n-1) + arr[n];
}
// Only change code above this line
}
var total = sum([2, 3, 4], 1);
console.log(total)

/* So…
We pass ‘1’ into the function sum([2, 3, 4], “1”<-)
Because it is not <= 0, the function returns the array (‘arr’), decrements ‘n’/index by 1 (meaning it is now 0). But before returning, asks the function to add the contents of ‘arr’ together (+ arr[n]), up until the index specified index [n], 1 in this case?

So it would look kind of like this,

sum([2,3,4],1)
sum([0],0) + [2+3] = 5

Feel free to make any corrections to my workings at here to give a more acurate depiction of what happens within the function. Thankyou so much…
*/

the function sum([2,3,4], 1) is called n is higher than 0 so this function returns the sum of an other function and a number, but n is decreased by 1: sum([2,3,4], 0) + 3
the function is called, this time n is 0 so the function returns arr[0], which is substituted instead of the function call
so sum([2,3,4], 0) becomes 2
and sum([2,3,4], 0) + 3 becomes 2+3 so 5