Review JavaScript Fundamentals by Building a Gradebook App - Step 4

JavaScript
1

Tell us what’s happening:

my friend use same coding can pass the test.
why i can not pass?
can you just advise the coding and correction for me
stuck here for so long
waste my so much time

Your code so far

function getAverage(scores) {
  let sum = 0;

  for (const score of scores) {
    sum += score;
  }

  return sum / scores.length;
}

function getGrade(score) {
  if (score === 100) {
    return "A++";
  } else if (score >= 90) {
    return "A";
  } else if (score >= 80) {
    return "B";
  } else if (score >= 70) {
    return "C";
  } else if (score >= 60) {
    return "D";
  } else {
    return "F";
  }
}

function hasPassingGrade(score) {
  return getGrade(score) !== "F";
}


// User Editable Region

function studentMsg(totalScores, studentScore) {
  let passFail
  if (hasPassingGrade(studentScore)) {
    passFail = "You passed the course."
  } else {
    passFail = "You failed the course."
  } 
  return "Class average:" + getAverage(totalScores) + ". Your grade:" + getGrade(studentScore) + ". " + passFail;
}
console.log(studentMsg([92, 88, 12, 77, 57, 100, 67, 38, 97, 89], 37));

// User Editable Region

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/125.0.0.0 Safari/537.36

Challenge Information:

Review JavaScript Fundamentals by Building a Gradebook App - Step 4

2

Compare your message to the expected, they are no quite the same:

"Class average:71.7. Your grade:F. You failed the course." // Yours
"Class average: 71.7. Your grade: F. You failed the course." // Expected
3

Hi there!
Add a semicolon after the variable declaration.

And give a space after each colon : within the return string.

4

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