Seek and Destroy filter()

JavaScript
1

Tell us what’s happening:

They tell us to use filter() but I’m having trouble using it to filter out anything where arr[i]===args[j].

Any tips on how to use filter correctly?

Thanks

Your code so far

function destroyer(arr) {
  // Remove all the values
  var args=arr.slice.call(arguments,1);
  var newArr=[];
  for (i=0; i<arr<length; i++) {
    for (j=0; j<args.length; j++) {
      newArr = arr.filter(Boolean(arr[i]===args[j]));
    }
  }
  
  return newArr;
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Your browser information:

Your Browser User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.36 Edge/16.16299.

Link to the challenge:
https://www.freecodecamp.org/challenges/seek-and-destroy

5

Okay I see what I need to do now, but can’t quite think of anything except arr[I]===args[j] .
Because of scope I cant reference array elements within the
This is all I can come up with so far.
Still wrong though and looks like bad code.
function destroyer(arr) {
// Remove all the values
args=arr.slice.call(arguments,1);
var newArr=[];
for (i=0; i<arr.length; i++) {
for (j=0; j<args.length; j++) {
newArr = arr.filter(function(arrElement){
if (arr[i]===args[j]) {
arrElement=args[j];
return arrElement;
}
}
);}
}

return newArr;
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

7

Okay I understand your example.

I think I just need to keep trying to understand what the code is doing every time I make a wrong code.

E.g. my code now returns [3,3].


function destroyer(arr) {
  // Remove all the values
  var args=arr.slice.call(arguments,1);
  var newArr=[];
  for (i=0; i<arr.length; i++) {
    for (j=0; j<args.length; j++) { 
      newArr = arr.filter(function(arrElement) {
        if (arr[i]===args[j]) {
        return arrElement ===args[j];
        }
       });
    
    }
  }
  
 return newArr;
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);
9

Thank you so much for your help!! Do you have your own course? you’re a great teacher!
Finally managed to create a solution but without both for loops.

function destroyer(arr) {
  // Remove all the values
  var args=arr.slice.call(arguments,1);
 
  
 var newArr = arr.filter(function(arrValue) {
    return args.includes(arrValue)==false; 
       
    });
  
  return newArr;
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

I’m still keen to see if there a way to do it with a for loop. I now understand that I don’t need a for loop for arr as that is part of arr.filter().
However when I did console log it showed true for some things that should be false and visa versa.

Should I use the for loop outside or inside the filter function? And can I reference args[i] in the filter function?

Thank you!