Seek and Destroy need help with my logic

JavaScript
1

Tell us what’s happening:

Can somebody help how to solve this task. I went over it several times and I cannot find my logical mistake. A hint would be great. Thanks :slight_smile:

Your code so far

function destroyer(arr) {
  // Remove all the values
  var result = arr.filter(newArr);
  
  function newArr(val) {
  for (var i = 1; i < arguments.length; i++) {
    for (var j = 0; j < arr.length; j++) {
        if(arguments[i] !== arr[j]) {
          return val;
        }
      }
    }
  }
    
  
  return result;
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

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Link to the challenge:
https://www.freecodecamp.org/challenges/seek-and-destroy

2

Look at what’s inside arguments:

function destroyer(arr) {
  console.log(arguments)
  // Remove all the values
  var result = arr.filter(newArr);
  
  function newArr(val) {
    console.log(arguments)
    for (var i = 1; i < arguments.length; i++) {
      for (var j = 0; j < arr.length; j++) {
        if(arguments[i] !== arr[j]) {
          return val;
        }
      }
    }
  }
    
  
  return result;
}

console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));
3

Arguments are what’s passed into the function. You’re working with two functions. Each function has its own arguments object.

4

The following is mine, there are simmilar way of thinking but different way of code

function destroyer(arr){
    //convert arguments into array
    
    var args = Array.from(arguments);
    
    //comparing the indexes of array and arguments
    //and delete if it's equal
    for(var i in arr){
        for(var j in args){
            if(arr[i] === args[j]){
                delete arr[i];
            }
        }
    }
    // the expected result of arr would contain some null values 
    //therefore, we need to filter() those null 
    return arr.filter(arr => Boolean(arr));
}
6

thanks for your reminding :slight_smile: