Select first in for loop

Python
1

in need to do something with the first in a for loop.
something like this
list = [1,2,3,4]
for i in list:
print(i)
print(i[0] )

2

More like this

list = [1,2,3,4]
for i in list:
    print(i)

The indentation (white space) is very important for Python.
This loop can be read or interpreted as: go over each element from list, assigning that item to a variable named i and then displaying that variable before next cycle.

print(i[0] )

It doesn’t make any sense there, mostly because i does not contain an index (like array, or collections). It is a number.

If you want to only do something with the first element in a list, you do not need a loop.

print(list[0])

If you were to give more details to what you are trying to do, you might get more information.

3

thanks for the reaction.
this is my solution for my problem
def bestanden_verwijderen():
try:
destination_map = glob.glob(“path/*”)
bestand_dat_weg_moet =
destination_map.sort(key=os.path.getmtime)
for bestanden in destination_map:
print(bestanden)
bestand_dat_weg_moet.append(bestanden)
print(bestand_dat_weg_moet[0])
os.remove(bestand_dat_weg_moet[0])
except:
print(‘er zijn geen bestanden’)
pass

to remove a file in order of creation.
im quite new in python and sorry for my english.
is this correct this way ?
or are there other options?