Solution for Rosetta Code: Element-wise operations

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#1

What is your hint or solution suggestion?

Most of the operations are only being performed on elements in subarrays. Use Array.map twice and arr[idx][idx2] to find out how to add the subarray elements together.

Solution 1 
function operation(op, arr1, arr2) {
    if(op=="m_add"){
        return arr1.map((subarray,idx) => 
               subarray.map((x,idx2) => x + arr2[idx][idx2]));
    }
    if(op=="m_sub"){
        return arr1.map((subarray,idx) => 
               subarray.map((x,idx2) => x - arr2[idx][idx2]));
    }
    if(op=="m_mult"){
        return arr1.map((subarray,idx) => 
               subarray.map((x,idx2) => x*arr2[idx][idx2]));
    }
    if(op=="m_div"){
        return arr1.map((subarray,idx) => 
               subarray.map((x,idx2) => x/arr2[idx][idx2]));
    }
    if(op=="m_exp"){
        return arr1.map((subarray,idx) => 
               subarray.map((x,idx2) => x**arr2[idx][idx2]));
    }
    if(op=="s_add"){
        return arr1.map((subarray) => 
               subarray.map((x) => x + arr2));
    }
}

Challenge: Element-wise operations

Link to the challenge:

#2