Sorted Union-Need Help

JavaScript
1

Tell us what’s happening:

I cannot figure out how to filter out the duplicates. Please help.

Your code so far

  let newArr = [];
  newArr.push(...arguments);
  console.log(newArr);
  let finalArr = [];
  let sortedArr = [];

  for (i = 0; i < newArr.length; i++) {
    for (j = 0; j < newArr[i].length; j++) {
      finalArr.push(newArr[i][j]);
    }
  }
  console.log(finalArr);
  sortedArr = finalArr.filter(function(item) {
    return item !== item;
  })

  return sortedArr;

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:62.0) Gecko/20100101 Firefox/62.0.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/intermediate-algorithm-scripting/sorted-union

3

Yes exactly. I merged the arrays into one so I can apply filter on only 1 array for duplicates.

4

I am just facing an issue in the filtering section. Cannot make logic for checking and removing duplicates.

5

So i was able to solve the problem.

function uniteUnique(arr) {
  let newArr = [];
  newArr.push(...arguments);
  console.log(newArr);
  let finalArr = [];
  let sortedArr = [];

  for (var i = 0; i < newArr.length; i++) {
    for (var j = 0; j < newArr[i].length; j++) {
      finalArr.push(newArr[i][j]);
    }
  }
  console.log(finalArr);
  sortedArr = finalArr.filter(function(item, index, self) {
    if(index == self.indexOf(item)) {
      return item;
    }
  })

  return sortedArr;


}

uniteUnique([1, 3, 2], [5, 2, 1, 4], [2, 1]);